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a 1g sample of naoh contaminated with na2co3 is titrated with 0.500MHCl, and it is found that 46.5mL of HCl are required for neutralization. Find the percentage by mass Na2Co3
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To find the percentage by mass of Na2CO3 in the contaminated NaOH sample, we can follow these steps:
1. Determine the moles of HCl used in the titration:
- We know the concentration of the HCl solution (0.500 M) and the volume used (46.5 mL).
- Convert the volume to liters: 46.5 mL = 0.0465 L.
- Use the formula: moles = concentration x volume.
Moles of HCl = 0.500 M x 0.0465 L.
2. Since NaOH and HCl react in a 1:1 ratio, the moles of HCl used will also equal the moles of NaOH present initially.
3. Determine the mass of NaOH used:
- We know the moles of NaOH from step 2, and the molar mass of NaOH is 39.997 g/mol (rounded to four decimal places).
- Use the formula: mass = moles x molar mass.
Mass of NaOH = Moles of NaOH x Molar mass of NaOH.
4. Determine the mass of Na2CO3 in the contaminated NaOH sample:
- The contamination ratio is unknown, so let's assume that for every mole of NaOH, there is 1 mole of Na2CO3 present.
- The molar mass of Na2CO3 is 105.988 g/mol (rounded to four decimal places).
- Use the formula: mass = moles x molar mass.
Mass of Na2CO3 = Moles of NaOH x Molar mass of Na2CO3.
5. Calculate the percentage by mass of Na2CO3:
- We know the mass of Na2CO3 and the initial mass of the sample (1 g).
- Use the formula: percentage by mass Na2CO3 = (mass of Na2CO3 / initial mass of the sample) x 100.