February 23, 2017

Homework Help: Chemistry

Posted by Natasha on Monday, April 21, 2008 at 10:41pm.

In a laboratory activity, a student team measures the heat released by burning heptane. Using the following data, calculate the molar heat of combustion of heptane in kJ/mol:

Mass of water - 179.2 g
Initial water temperature - 11.6 degrees C
Final water temperature - 46.1 degrees C
Mass of heptane burned .585 g

Ok so the heat would be
(179.2)(34.5)(4.18) = 25842.43 J = 25.84 kJ, right?

And then the heat of combustion would be 25.84/44.17 = 44.17, right?

So what do I do after this? Is what I did even right?

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