The Sun puts out 3.9 x 10^26 J of energy per second. Assuming 100% conversion to energy, how much mass is required to create this energy
I'm sorry, but I really, really need help with this, but it's due tomorrow and I'm so lost..
Start with
Energy= mass*speedlight^2
solve for mass. If speedlight is in m/s, and energy in joules, then mass will be in kilograms.
omg thank you for much!!! :>
To calculate the mass required to create this amount of energy, we can use Einstein's famous equation, E=mc², where E is the energy, m is the mass, and c is the speed of light (approximated as 3 x 10^8 m/s). Rearranging the equation, we have m=E/c².
Given that the Sun puts out 3.9 x 10^26 J of energy per second, we can substitute this value into the equation:
m = (3.9 x 10^26 J) / (3 x 10^8 m/s)²
First, let's compute (3 x 10^8 m/s)²:
(3 x 10^8 m/s)² = 9 x 10^16 m²/s²
Now, we can substitute this value into the equation:
m = (3.9 x 10^26 J) / (9 x 10^16 m²/s²)
Next, we simplify and cancel out units:
m = (3.9 x 10^26) / (9 x 10^16) kg
To simplify further, we divide the numerator and denominator by 9 x 10^16:
m = 4.33333333 x 10^9 kg
Therefore, approximately 4.33 x 10^9 kilograms (or 4.33 billion kilograms) of mass would be required to produce the energy output of the Sun per second if 100% conversion efficiency were achieved.