Tuesday

November 25, 2014

November 25, 2014

Posted by **Dennis** on Monday, April 21, 2008 at 9:59am.

cos[arccos(-sqrt3/2)-arcsin(-1/2)]

This is what I have:

cos [(5pi/6)-(11pi/6)]

cos (-6pi/6) or -pi

giving an answer of -1

What I am wondering is should I use the (11pi/6) or should I use (-pi/6) because of the restrictions on arcsin x (-pi/2)<=x<=(pi/2)

Thank you in advance.

- Inverses -
**bobpursley**, Monday, April 21, 2008 at 11:14amI would use the smaller angle. It should not matter on the final answer.

- Inverses -
**Dennis**, Monday, April 21, 2008 at 11:35amThank you very much.

The answer doesn't change, but my trig teacher wants to see all of work, and I just wasn't sure which figure to use.

**Answer this Question**

**Related Questions**

Trig/PreCalc - Teach me how to express 5sqrt3 - 5i in polar form please. I don't...

Trigonometry - Checking my work - Find the sum of the three smallest positive ...

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...

Precalculus check answers help! - 1. Which expression is equivalent to cos ...

PRECALCULUS - find the cube roots of the complex number. 27((cos(11pi/6)) + i(...

Pre Cal. - Express 5sqrt(3) - 5i in polar form. A: 10(cos(11pi/6) + i sin(11pi/6...

maths - Find the roots of z^6 + 1 and hence resolve z^6 + 1into read quadratic ...

maths - Find the roots of z^6 + 1 and hence resolve z^6 + 1into read quadratic ...

math - how to define arc cosine(cosine x) for -360 deg<x< 360 deg?? a ...