Posted by Johnson on Sunday, April 20, 2008 at 11:28am.
Compute the number of moles n first. You can then say that:
n = n_{N2} + n_{O2}
You also know that:
n_{N2}/n = 0.79
and
n_{O2}/n = 0.79
This allows you to solve for n_{N2} and n_{O2}. Using the molar masses for N2 and O2 you can then obtain the mass.
Air is a mixture of nitrogen, oxygen, and other gases.
At STP, one mole of an ideal gas occupies 22.4 liters.
Assume air is 21% O2 and 79% N2 by volume
0.21 x 32 g/mol + 0.79 x 28 g/mole = 28.8 g / mol of "air"
28.8 g / 22,400 mL = 0.0013 g/mL
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