Posted by rudy on Saturday, April 19, 2008 at 8:57pm.
lim
x> infinity
1/(sqaure root of 4/x^2 plus one)
i don't understan why the answer is 1.

math  Anonymous, Saturday, April 19, 2008 at 9:11pm
as x approaches infinity, the term 4/x^2 becomes a very small number. So, the formula basically becomes:
1/square root(1), which equals 1.