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September 1, 2014

September 1, 2014

Posted by **Lucy** on Saturday, April 19, 2008 at 4:03pm.

A) sin^2 theta + cot^2 theta sin^2 theta

B) (sin^2 theta/1-cos theta)-cos theta

C) sec^2 theta + tan^2 theta

D) cot^2 theta sin^2 theta/cos^2theta

Answer: D

- Algebra II -
**Damon**, Saturday, April 19, 2008 at 6:42pmfor D I get

c^2/s^2 * s^2 /c^2 = 1 sorry

A gives

s^2 (1 + c^2/s^2) = s^2 + c^2 = 1

B gives (does not make sense the way you wrote it)

Maybe you mean

sin^2 theta/(1-cos theta)-cos theta

[s^2 -c (1-c)] /(1-c)

[ s^2 + c^2 -c] / (1-c)

(1-c) / (1-c)

1

C gives

(1/c^2) + s^2/c^2

= (1 + s^2)/c^2

not 1

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