Posted by **Pierre** on Saturday, April 19, 2008 at 1:19pm.

An apartment has a living room whose dimensions are 2.5 m 4.8 m 5.9 m. Assume that the air in the room is composed of 79% nitrogen (N2) and 21% oxygen (O2). At a temperature of 27°C and a pressure of 1.01 105 Pa, what is the mass (in grams) of the air?

g

- Physics -
**Damon**, Saturday, April 19, 2008 at 5:28pm
V = 2.5 * 4.8 * 5.9 = 70.8 m^3

N is 14 so N2 is 28 grams/mole

O is 16 so O2 is 32 grams/mole

so a mole of "air" has mass of .79*28 + .21*32 = 28.8 grams/mole

assume air is ideal gas

P V = n R T

1.01 * 10^5 * 70.8 = n * 8.3145 *(273+27)

n = 3037 moles

3037* 28.8 = 87468 grams

- Physics -
**Pierre**, Sunday, April 20, 2008 at 4:44am
my teacher says this is the incorrect answer. what could be wrong

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