Posted by Anonymous on .
1)AP has U6=12.5 and U19=32
(a)What is the nth term?Tn=5+(n-1)1.5
(b)What is the sum of 4 terms between U10 and U13 inclusive?
(a)What is the nature of this sequence?
(b)Calculate the sum of the first nine terms?
(b)If Wm=2+5m, when is Wm first a three digit number?
(c)Find m for the case where Wm=U10
for 1. a) I would simplify a bit further.
= 5 + 1.5 n - 1.5
= 1.5n + 3.5
find the sum of the first 13 terms, then
find the sum of the first 9 terms.
2. Clearly a geometric sequence if the expression is (1/2)^(n-3)
The problem is that you did not specify the starting value of n
e.g. if you start with n = 4, term 1 is 1/2
if you start with n = 1 then the first term is 4
In any case r = 1/2
Use you sum formula to find the sum of 9 terms.
3. obviously an arithmetic sequence with a= 11.5 , d= -.5
Sum(n) = n/2[2a + (n-1)d]
0 = n/2[23 - .5(n-1)]
solve for n