chemistry
posted by Anna .
If the concentration of Pb2+ is found to be 2.3 x 109 mol/L in a saturated solution of Pb3(PO4)2, what is the Ksp of Pb3(PO4)2 ?
This is my work thus far it is as far as I could get:
Ksp = [Pb2+] [Pb3(PO4)2]
= [2.3 x 109 mol/L][Pb3(PO4)2]

Try this:
Ksp = [Pb2+]^3 [PO4]^2
= (2.3E9)^3 (2/3 * 2.3E9)^2
= 4/9 * (2.3E9)^5
Hardly soluble stuff. Notice if the Pb ion concentration is x, then the PO4 ion has to be 2/3 x.....from the ratios in the formula.