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July 4, 2015

Homework Help: Algebra

Posted by Anonymous on Friday, April 18, 2008 at 6:29pm.

Is this right?


Decompose into partial fractions.

(2x^2-24x+35)/(x^2+2x-7)(x-2)=
(Ax+B)/(x^2+2x-7)+C/(x-2)

=Ax^2+Bx-2Ax-2B+Cx^2+2xC-7C
=(A+C)x^2+Bx+2(Ax+Cx-B)-7C
A+C=2
2Ax+Bx+2Cx=24
-2B-7C=35
A=2-C
B=(35-7C)/(-2)

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