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July 4, 2015

Homework Help: Algebra

Posted by Tim on Friday, April 18, 2008 at 5:48pm.

Below is my problem with my answers. I don't think this is that tough, but I cannot believe that my ABC answer's are a fraction. Did I do this correctly?

Find the unknowns on the right side of the partial fraction.

(x+3)/(x^3+64)=(A)/(x+4)+(Bx+C)/(x^2-4x+16)

x=0
A= (-x^2B-4xB-x+x-4C+3)/(x^2-4x+16)
B= (-x^2A+4xA-x(-16A+x-4C+3)/(x(x+4)
C= (-x^2B-4xB-x^2A+4x+x-16A+3)/(x+4)

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