Friday

April 17, 2015

April 17, 2015

Posted by **JaneLee** on Friday, April 18, 2008 at 1:11pm.

3^5x+1= 40 and log6X+(log6)7=(log6)35

I hope that makes sense because logs are hard to type.

- Algebra 2 -
**Reiny**, Friday, April 18, 2008 at 3:01pm-5=log2X

-5 = log_{2}x

2^-5 = x

x = 1/32

3^(5x+1)= 40

let's take the log of both sides

log(3^(5x+1)) = log40

(5x + 1) log3 = log40

5x+1 = log40/log3

etc.

log6X+(log6)7=(log6)35

log_{6}(7x) = log_{6}35

"antilog" both sides

7x = 35

etc.

**Answer this Question**

**Related Questions**

Logs - log6(x+7)−log6x=2 Solve for x

Math - Solve the equation. (the 6s are supposed to be sub-scripted, but I can't ...

precalulus - Ok feeling kinda dumb because this isn't coming out right. I know ...

Math - log6(x+7)−log6x=2 Solve for x

Math SAT Sheet - 1.) Find the domain and range for: f(x)= 4x-20/ the square ...

Math - The problem I have to solve is log with base 2 ^6 multiply by log base 6...

Math - Which of the following is equal to log6(t + 1) − log6(t^2 − 1...

Logarithmic Algebra - let log2=a, log3=b, and log5=c. express the indicated ...

algebra - Beer cans are right circular cylinders. My Algebraic Ale and ...

Intermediate college algebra - Beer cans are right circular cylinders. My ...