Homework Help: Algebra 2

Posted by JaneLee on Friday, April 18, 2008 at 1:11pm.

Can someone please explain to me how to solve logarithmic equations? Some examples are: -5=log2X
3^5x+1= 40 and log6X+(log6)7=(log6)35
I hope that makes sense because logs are hard to type.

Algebra 2 - Reiny, Friday, April 18, 2008 at 3:01pm
-5=log2X

-5 = log₂x

2^-5 = x
x = 1/32

3^(5x+1)= 40
let's take the log of both sides

log(3^(5x+1)) = log40
(5x + 1) log3 = log40
5x+1 = log40/log3
etc.

log6X+(log6)7=(log6)35
log₆(7x) = log₆ 35
"antilog" both sides
7x = 35
etc.

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