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September 30, 2014

September 30, 2014

Posted by **JaneLee** on Friday, April 18, 2008 at 1:11pm.

3^5x+1= 40 and log6X+(log6)7=(log6)35

I hope that makes sense because logs are hard to type.

- Algebra 2 -
**Reiny**, Friday, April 18, 2008 at 3:01pm-5=log2X

-5 = log_{2}x

2^-5 = x

x = 1/32

3^(5x+1)= 40

let's take the log of both sides

log(3^(5x+1)) = log40

(5x + 1) log3 = log40

5x+1 = log40/log3

etc.

log6X+(log6)7=(log6)35

log_{6}(7x) = log_{6}35

"antilog" both sides

7x = 35

etc.

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