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December 21, 2014

December 21, 2014

Posted by **Nik** on Friday, April 18, 2008 at 4:33am.

- Physics -
**Damon**, Friday, April 18, 2008 at 5:20amI w

I w = 2 (M/L) integral from 0 to L/2 of (x sin B)^2 dx * w

= 2 w (M sin^2 B/L) integral 0 to L/2 of x^2 dx

= 2 w (M sin^2 B / L) x^3/3 at x = L/2 - at x = 0

= (2/3) w (M sin^2 B / L) L^3/8

= (1/12) w M L^2 sin^2 B

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