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A thin rod of length L and mass M rotates about a vertical axis through its center with angular velocity w. The rod makes an angle B with the rotation axis. Determine the angular momentum of the rod.

  • Physics -

    I w

    I w = 2 (M/L) integral from 0 to L/2 of (x sin B)^2 dx * w

    = 2 w (M sin^2 B/L) integral 0 to L/2 of x^2 dx

    = 2 w (M sin^2 B / L) x^3/3 at x = L/2 - at x = 0

    = (2/3) w (M sin^2 B / L) L^3/8

    = (1/12) w M L^2 sin^2 B

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