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October 1, 2014

Homework Help: Chemistry to DrBob

Posted by Amy on Friday, April 18, 2008 at 1:25am.

Dr. bob could you please check this work cus i can't seem to get it right

the first step of the synthesis is described by the reaction below. When 1.750 g of Fe(NH4)2(SO4)2 6H2O is mixed with 13 mL of 1.0 M H2C2O4, the theoretical yield of FeC2O42H2O is ????
grams.

Fe(NH4)2(SO4)26H2O(s) + H2C2O4(aq)-->
FeC2O42H2O(s) + (NH4)2SO4(aq) + H2SO4(aq) + 4 H2O(l)

1.750g Fe(NH4)2(SO4)2 6H2O x(1 molFe(NH4)2(SO4)2 6H2O/392.1g)(1mol FeC2O42H2O/1mol Fe(NH4)2(SO4)2 6H2O )= 4.46x10^-3 moles of product formed from Fe(NH4)2(SO4)2 6H2O

3 mL(1L/1000ml)(1mol H2C2O4/L)( 1mol FeC2O42H2O/1mol H2C2O4)= 1.3x10^-2moles of product formed from H2C2O4

(4.46x10^-3 moles of FeC2O42H2O)(392.1g FeC2O42H2O/ 1 mol)= 1.75g FeC2O42H2O produced

I GOT THAT WRONG.

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