An aspirin tablet weighing 0.650 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved

the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL
of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution.
The concentration of the diluted solution is

To calculate the concentration of the diluted solution, we need to determine the moles of ASA (acetylsalicylic acid) present in the 3.00 mL of solution pipetted into the 100 mL volumetric flask, and then adjust for the dilution.

Step 1: Calculate the moles of ASA in 0.650 g tablet:
Mass of ASA = 68.2% x 0.650 g = 0.443 g
Moles of ASA = Mass of ASA / Molar mass of ASA
Molar mass of ASA = 180.16 g/mol
Moles of ASA = 0.443 g / 180.16 g/mol = 0.002459 mol

Step 2: Calculate the concentration of ASA in the 3.00 mL solution:
Moles of ASA in 3.00 mL = Moles of ASA in 0.650 g tablet x (3.00 mL / 250 mL)
Moles of ASA in 3.00 mL = 0.002459 mol x (3.00 mL / 250 mL) = 2.9512 x 10^(-5) mol

Step 3: Calculate the concentration of the diluted solution:
Concentration (Molarity) = Moles / Volume (in liters)
Volume of solution = 100 mL = 0.1 L

Concentration = Moles / Volume
Concentration = (2.9512 x 10^(-5) mol) / (0.1 L)
Concentration = 2.9512 x 10^(-4) M

Therefore, the concentration of the diluted solution is 2.9512 x 10^(-4) M.

To find the concentration of the diluted solution, we need to know the amount of ASA (acetylsalicylic acid) present in the 3.00 mL pipetted solution and the volume of the final diluted solution in the 100 mL volumetric flask.

Let's calculate the amount of ASA in the initial solution:

Mass of the tablet = 0.650 g
Percentage of ASA = 68.2%

Amount of ASA in the tablet = percentage of ASA × mass of the tablet
= 68.2% × 0.650 g
= 0.443 g

Now, let's calculate the concentration of the diluted solution:

Amount of ASA in the 3.00 mL solution = amount of ASA in the initial solution × (volume of the final diluted solution / volume of the pipetted solution)
= 0.443 g × (100 mL / 3.00 mL)
= 14.77 g

Concentration of the diluted solution = amount of ASA in the 100 mL solution / volume of the final diluted solution
= 14.77 g / 100 mL
= 0.1477 g/mL

Therefore, the concentration of the diluted solution is 0.1477 g/mL.

The question leaves a little to be desired. Do you want the concn in grams/mL, grams in total volume, molarity, and/or do you want the concn of the tablet?

I suspect you want the concn in g/mL in the final 100 mL volumetric flask. If that isn't so then clarify the question and repost.
0.650 x 0.682 = ?? g ASA in the tablet.

??g ASA placed in 250 mL flask. concn now ??g/250 mL = xx g/mL.
We take 3 mL and dilute to 100 so it is not xxg/mL x 3/100 = yy g/mL.
You can divide the yy by 180.16 to obtain the mols/mL and then change to to mols per 1 L to get M.Check my thinking. Check my work.