Posted by **Alex** on Thursday, April 17, 2008 at 9:41pm.

Someone please explain these!

The angle between two planes is defined as the angle between their normals. Determine the angle theta between 0 and 90 degrees between the given planes.

a) 2x+3y-z+9 = 0 and x+2y+4 = 0

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If the positive z-axiz points up, show that the line x=0, y=t, z=2t is parallel to and below the plane 2x-10y+5z-1 = 0.

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Find an equation for the set of points P(x,y,z) that are equidistant from the points A(1,2,3) and B(4,0,1)

- Math -
**Reiny**, Friday, April 18, 2008 at 9:15am
Love these kind of questions.

1. normals are (2,3,-1) and (1,2,0)

a∙b = │a││b│cosß

2+6+0 = (√14)(√5)cosß

cosß=8/√70

ß will be the angle between the normals, can you take it from here?

2. The line has direction (0,1,2) and the plane has a normal of (2,-10,5)

take the dot product.

If the normal is perpendicular to the line, shouldn't the line be paralle to the plane?

3. vector AB = (3,-2,-2)

this would be a normal to the plane, so the equation of the plane is

3x - 2y - 2z = C

Shouldn't this plane pass through the midpoint of AB ??

I am sure you can take it from there.

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