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July 29, 2014

July 29, 2014

Posted by **Chelly** on Thursday, April 17, 2008 at 8:07pm.

A: If the rocket ship's speed is 0.500 c, calculate the time for the trip, as measured by people on earth.

B: If the rocket ship's speed is 0.500 c, calculate the time for the trip, as measured by astronauts in the rocket ship.

I'm quite confused about which equation to use for which part... Any help is immensily appreciated!

- Physics -
**Count Iblis**, Thursday, April 17, 2008 at 10:12pmYou can solve all such problems using the fact that a distance in Space-Time between two points is defined as:

S^2 = (distance in time)^2 - (distance in space)^2

The distance in time is defined as the difference in the time coordinate times c (the speed of light).

Because S is a distance betwen two points it does not matter in which reference frame you evaluate it.

Let's compute S^2 between the two points defined as:

1) Spaceship leaves Earth

2) Spaceship arrives at Betelgeuse

According to an observer at Earth, the travel time will be 1000 years. The spatial distance is 500 lightyears. This means that:

S^2 = 1000^2 - 500^2 = 7.5*10^5 year^2

(I've put speed of light equal to 1 and I'm thus measuring spatial distances in years. I.e. 1 lightyear = 1 year in these units)

Now, we can also evaluate S^2 in the reference frame of the observer. If we do that, we should, of course, find the same result. However, we don't know the time difference between the two points. We do know that the difference in spatial coordinate is now zero.

If we call the travel time in the reference frame of the observer T, then we have:

S^2 = T^2 ------->

T = sqrt[7.5*10^5] years =

866 years.

- HELP!!!!! !!!! -
**Chelly**, Friday, April 18, 2008 at 12:25amWhen I use the above I get correct answers for 2 different values, but when the given is .9999c, I don't get a correct answer... Why??

There is also a C Part:

If the rocket ship's speed is 0.9999c, calculate the energy needed in joules.

How do I convert to this??

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