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November 29, 2015
Posted by **Jonathan** on Thursday, April 17, 2008 at 1:45pm.

thanks ... :)

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**bobpursley**, Thursday, April 17, 2008 at 1:51pmThe first pairing says that sinA is -4/5

If cosB is 12/13, then sinB is 7/13

Sin(A-B)=CosASinB-SinACosB, right?

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**Jonathan**, Thursday, April 17, 2008 at 1:52pmyeah thats right, can u go on?

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**bobpursley**, Thursday, April 17, 2008 at 1:55pmI could, but I wont. However, I will be happy to critique your work or thinking

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**bobpursley**, Thursday, April 17, 2008 at 1:58pmError: sinA=-3/5

in all cases, sin^2 Theta + cos^2 Theta=1

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**Jonathan**, Thursday, April 17, 2008 at 1:58pmwell, i got:

(-4/5)(12/13) - (4/5)(7/13)

therefore

(-48/65) - (28/65)

therefore:

answer = (-76/65)

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**Reiny**, Thursday, April 17, 2008 at 1:59pmfrom if cosA = 4/5; sin <0 we know that A is in the fourth quadrant and sinA = -3/5

from cosB = 12/13; 0<B<90 we know sinB = 5/13

sin(A-B) = sinAcosB - cosAsinB

= (-3/5)(12/13) - (4/5)(5/13)

= -56/65

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**bobpursley**, Thursday, April 17, 2008 at 1:59pmchange the Sin A in the first term, and it works.

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**Jonathan**, Thursday, April 17, 2008 at 1:59pmi knew that was wrong, coz my answer should be in the 50's haha..thanks though, great help

can i ask how you got sinA and sinB with that information :)

no point in me just copying it i would like to know how you got it

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**bobpursley**, Thursday, April 17, 2008 at 2:02pmIn any angle, the sum of the squares of the cosines and sines is equal to one. Use that to solve.