Saturday
February 28, 2015

Homework Help: CHEMISTRY- PLEASE HELP:)!

Posted by Miley on Wednesday, April 16, 2008 at 9:46pm.

Pure lauric acid is melted and the freezing point is determined to be 43 degrees celsius.

A solution is made by dissolving .50 grams of paradicholrobenzene into 3.00 grams of lauric acid.
Determine the molality of this solution. I got 1.1m. which is right.

But then it says the freezing point of the mixture is measured and found to be 39 degrees celsius. Then it says... determine the freezing poitn constant (kf) for lauric acid. how do i do that?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

lauric acid - what happens to the calculated molar has if the lauric acid is ...
chem - A solution prepared by dissolving 3.00 grams of ascorbic acid (vitamin C...
chemistry - 1) The color of bromocresol green indicator is??? when pH < 4, ...
chemistry... please help! - Pure glacial acetic acid HC2H3O2 has a freezing ...
Chemistry - calculate the freezing point of a solution containing 12.2 grams of ...
chemistry - A) A student performed the freezing point depression experiment ...
chemistry - (A) A student performed the freezing point depression experiment ...
Chemistry - 0.15 grams of benzene (C6H6) is dissolved into 4.7 grams of melted ...
chemistry - 0.24 grams of benzene (C6H6) is dissolved into 4.9 grams of melted ...
Chemistry - Pure benzene has a normal freezing point of 5.50 degrees Celsius. A...

Members