Saturday
April 19, 2014

Homework Help: CHEMISTRY- PLEASE HELP:)!

Posted by Miley on Wednesday, April 16, 2008 at 9:46pm.

Pure lauric acid is melted and the freezing point is determined to be 43 degrees celsius.

A solution is made by dissolving .50 grams of paradicholrobenzene into 3.00 grams of lauric acid.
Determine the molality of this solution. I got 1.1m. which is right.

But then it says the freezing point of the mixture is measured and found to be 39 degrees celsius. Then it says... determine the freezing poitn constant (kf) for lauric acid. how do i do that?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry... please help! - Pure glacial acetic acid HC2H3O2 has a freezing ...
Chemistry - Pure benzene has a normal freezing point of 5.50 degrees Celsius. A...
chem - A solution prepared by dissolving 3.00 grams of ascorbic acid (vitamin C...
Chemistry - calculate the freezing point of a solution containing 12.2 grams of ...
chemistry - 0.24 grams of benzene (C6H6) is dissolved into 4.9 grams of melted ...
Chemistry - 3.92g of a nondissociating compound are dissolved in 400.g of liquid...
Chemistry - A solution was made by dissolving 62.07 grams of a compound in 500g ...
chemistry - this is a really long question. i don't understand how to answer it...
chemistry - A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in ...
chemistry - A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in ...

Search
Members