Posted by **Anna** on Wednesday, April 16, 2008 at 8:06pm.

Suppose you have a perfectly spherical water tank with an inside diameter of 8.6 metres. If the drain at the bottom of the tank can't handle a hydrostatic pressure of more than 50 kilopascals, what is the maximum volume of water, in litres, that can be contained in the tank? Assume that gravitational acceleration is exactly 9.81 m/s2.

- Physics -
**Damon**, Wednesday, April 16, 2008 at 9:11pm
The pressure is determined by the height of water in the tank.

P = rho g h

rho is about 1000 kg/m^3

g is 9.81

P is 50 *10^3 Pascals

solve for h in meters

then the radius of the tank is 4.3 meters and it is filled to depth h

volume of water = (1/6) pi h (3 rh^2 +h^2)

where rh is the radius at the water surface with depth h so rh = sqrt (2Rh-h^2)

then convert those m^3 to liters

- Physics -
**Enty**, Thursday, April 17, 2008 at 2:06am
Stop trying to cheat at neopets, it ruins it for the people who actually do the math.

- Physics -
**carla**, Saturday, April 19, 2008 at 12:38am
296,1

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