Monday

January 26, 2015

January 26, 2015

Posted by **Andrea** on Wednesday, April 16, 2008 at 6:12pm.

theda 1=60

n1= 1 (air)

What would n2 be for clear ice? I know that index of refraction for water is 1.33. Would it also be 1.33?

Snell's law states that:

(sin theda 1/ sin theda 2) = (n2/n1)

sin 60 / sin theda 2 = 1.33/1(that is if n2 is 1.33)

theda 2 turns out to be 40.6 degrees. The question asks for the angle between reflected and refracted rays. Would that make 160 degrees as the final answer? Or is the final answer just 40.6 degrees?

**Answer this Question**

**Related Questions**

physics/light reflection - A light of ray is incident at an angle of 58degrees ...

physics - A light of ray is incident at an angle of 58degrees on the plane ...

physics - A light of ray is incident at an angle of 58degrees on the plane ...

Physics - A ray of light stikes a flat 2 cm thick block of ice (n=1.5) at an ...

Physics - 1) The speed of light in a certain liquid is 3/5 the speed in a vacuum...

Physics - 1) The speed of light in a certain liquid is 3/5 the speed in a vacuum...

physics - A beam of light is incident on a flat piece of polystyrene at an angle...

Physics - The incident ray comes at 30 degrees to normal at the air/glass ...

Geometric & Wave Optics - A beam of light wavelenght 560 to availing in air is ...

Physics - Light is incident from water onto a flat transparent slab of material...