Posted by **Steven** on Wednesday, April 16, 2008 at 1:22pm.

can someone tell me wich one of the two answers for these two limits is correct?

lim (-1)^(n) = 1 or -1

n-> +infinity

lim (-1)^(n) = 1 or -1

n-> -infinity

Thanks in advance.

- calculating infinity -
**Reiny**, Wednesday, April 16, 2008 at 1:59pm
depends on n

if n is even then the answer is +1

if n is odd you get -1

for:

lim (-1)^(n) = 1 or -1

n-> -infinity

is really the same as

lim 1/(-1)^(n)

so the same reasoning as above applies

- calculating infinity -
**Steven**, Wednesday, April 16, 2008 at 3:47pm
1) I get it, except for

lim (-1)^(n) = ?

n-> +infinity

is infinity even or odd?

This is important because the result determines wheter the series that i was given is convergent or divergent.

2) in another excercise I encauntered the following problem:

is the following calculation with infinity allowed?:

lim (ln (n))^(1/n) = (ln (inf.))^(0)=1

n-> +inf.

Again txs for answering.

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