Posted by Anonymous on Wednesday, April 16, 2008 at 1:10pm.
Assume the ball starts its upward flight from the top of the throwers head, 1.75m above the ground.
1--Time to maximum height above the thrower's head derives from Vf = Vo - 9.8t or 0 = 5.376 - 9.8t making t(up) = .548sec.
2--Time back to the top of the throwers head is also .548sec. and the velocity the same as the departure velocity, 5.376m/s.
3--The time to reach the ground from the height of 21 + 1.75 = 22.75m = Vot + 9.8t^2/2 or 4.9t^2 + 5.376t - 22.75 = 0.
4--Solve for t using the quadratic formula.
5--Having t, the horizontal distance traveled becomes 14.004(.548 + .548 + t)
15.3
Related Questions
Physics - A hiker throws a ball at an angle of 21.0 degrees above the horizontal...
Science (Physics) - 1.A hiker started to walk from her campsite heading east ...
physics - A boy throws a ball at 5.5 m/s at an angle of 25.4° above the ...
Physics - A quarterback makes a pass, throwing the ball at 21 m/s and an angle ...
Physics - A quarterback makes a pass, throwing the ball at 21 m/s and an angle ...
physics - A hiker climbs a hill 300m high.If she weighs 50kg,calculate the work ...
Physics: Vectors - A hiker walks 10.0 km[NE], 5.0 km[W], and then 2.0 km[S] in 2...
Physics - A basketball player attempting a free throw shoots the ball at an ...
physics - Julie throws a ball to her friend Sarah. The ball leaves Julie's ...
Physics - If a box is being pulled up a hill at an angle to find work, its W=...
For Further Reading