Post a New Question

maths

posted by .

Is this right, and where do i go from here???
solve p-1/2-p-2/3=1
(3p-3)-(2p-4)/6=1

  • maths -

    The way you put it, there's no multiplication... so I don't know where you get 3p and 2p... maybe you want to revise your original problem by addiing in the parentheses.

    Anyway, by the way you put it... it should be:
    p-p-1/2-2/3=1 (combine like-terms)
    0-3/6-4/6=1 (common denominator)
    -7/6=1 (subtraction)

    ... and you end up with a false statement, yep, you need to revise your problem so people can read it correctly.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question