Posted by shay on Wednesday, April 16, 2008 at 9:39am.
Is this right, and where do i go from here???
solve p1/2p2/3=1
(3p3)(2p4)/6=1

maths  Jake1214, Wednesday, April 16, 2008 at 12:20pm
The way you put it, there's no multiplication... so I don't know where you get 3p and 2p... maybe you want to revise your original problem by addiing in the parentheses.
Anyway, by the way you put it... it should be:
pp1/22/3=1 (combine liketerms)
03/64/6=1 (common denominator)
7/6=1 (subtraction)
... and you end up with a false statement, yep, you need to revise your problem so people can read it correctly.
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