Posted by Joseph on Tuesday, April 15, 2008 at 10:45pm.
For the reactions that occurred spontaneously in the individual tables, balance these reactions assuming they are in an acidic solution.
I 2(aq) Cu2 + (aq) Ag + (aq) Br2 (aq)
Ag + (aq) Pb2 + (aq) Cu2 + (aq) Zn2 +(aq)
Br - (aq) Cl - (aq) I - (aq)
- chemistry - DrBob222, Tuesday, April 15, 2008 at 11:02pm
Your notation is still somewhat confusing to me but here is what you do for one of the reactions. The others are done the same way.
For the copper, Ag^+ reaction:
Cu ==> Cu^+2 + 2e
Ag^+ + e ==> Ag
The electrons must be kept equal; therefore, multiply the first equation by 1 and the second equation by 2, then add them.
Cu + 2Ag^+ ==> Cu^+2 + 2Ag.
The others are done the same way.
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