posted by Joseph .
For the reactions that occurred spontaneously in the individual tables, balance these reactions assuming they are in an acidic solution.
I 2(aq) Cu2 + (aq) Ag + (aq) Br2 (aq)
Ag + (aq) Pb2 + (aq) Cu2 + (aq) Zn2 +(aq)
Br - (aq) Cl - (aq) I - (aq)
Your notation is still somewhat confusing to me but here is what you do for one of the reactions. The others are done the same way.
For the copper, Ag^+ reaction:
Cu ==> Cu^+2 + 2e
Ag^+ + e ==> Ag
The electrons must be kept equal; therefore, multiply the first equation by 1 and the second equation by 2, then add them.
Cu + 2Ag^+ ==> Cu^+2 + 2Ag.
The others are done the same way.