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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Tuesday, April 15, 2008 at 8:29pm.

My work:

= limit, x -> a, (x^2 + 8ax + 16a^2 - 25a^2) / (x - a)

= limit, x -> a, (x^2 + 8ax - 9a^2) / (x - a)

= limit, x -> a, (x + 8a - 9a^2) / (-a)

= (a + 8a - 9a^2) / (-a)

= 9a^2 - 8a + 1

Textbook Answer: 10a

What did I do wrong, please correct it?

- Calculus; Limits -
**Count Iblis**, Tuesday, April 15, 2008 at 9:53pmMy work:

= limit, x -> a, (x^2 + 8ax + 16a^2 - 25a^2) / (x - a)

= limit, x -> a, (x^2 + 8ax - 9a^2)/

(x - a)

x^2 + 8ax - 9a^2 = (x-a)(x+9a)

Therefore:

(x^2 + 8ax - 9a^2)/(x - a) = (x+9a)

Lim x ---> a of (x+9a) = 10 a

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