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January 31, 2015

January 31, 2015

Posted by **Katie** on Tuesday, April 15, 2008 at 7:51pm.

(n/n-2)+(n/n+2)=(n/n^2-4)

I know that the LCD of the equation is (n+2)(n-2) because that is what you get when you factor out the n^2-4 in the last part of the question. I thought I did it right until I reached the end where I don't know how to solve it.

- ALGEBRA -
**Reiny**, Tuesday, April 15, 2008 at 8:02pmSo why not multiply each of the three terms by that LCD that you found to get

n(n+2) + n(n-2) = n

expand and solve as a quadratic.

I factors very nicely and has 2 simple answers.

- ALGEBRA -
**Katie**, Tuesday, April 15, 2008 at 8:06pmThat's just it. I don't know how to factor it out because i keep getting 2n^2-n=0

- ALGEBRA -
**Reiny**, Tuesday, April 15, 2008 at 8:25pm2n^2 - n = 0 is correct.

Now take out a common factor

n(2n-1) = 0

n=0 or n = 1/2

- ALGEBRA -

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