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chemistry

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Reaction 1:
Cu (strongest reducing agent)
I-
Ag
Br- (weakest reducing agent)

Reaction 2:
Zn(strongestreducing agent)
Pb
Cu
Ag(weakest reducing agent)

Reaction 3:
Cl2 (strongest oxidizing agent)
Br2
I2 (wekest oxidizing agent)

Using these results, how am I supposed to prepare a single table of relative strengths of oxidizing and reducing agents?

Thanks

  • chemistry - ,

    Reaction 1.
    Cu (strongest reducing agent)
    I-
    Ag
    Br- (weakest reducing agent)

    Reaction 2:
    Zn(strongestreducing agent)
    Pb
    Cu
    Ag(weakest reducing agent)

    Reaction 3:
    Cl2 (strongest oxidizing agent)
    Br2
    I2 (wekest oxidizing agent)

    Using these results, how am I supposed to prepare a single table of relative strengths of oxidizing and reducing agents?
    What happens if you put 1 and 2 together?
    #1.
    Cu (strongest reducing agent)
    I-
    Ag
    Br- (weakest reducing agent)
    #2.
    Zn(strongestreducing agent)
    Pb
    Cu
    Ag(weakest reducing agent)

    So it seems to me, forgetting #3 for the moment, that it's almost done for you.#2 tells you Zn, and Pb are at the top (above Cu and Ag) and follow that from #2 with Cu, I^-, Ag, Br^-. Then a look at #3 tells you that Br2 and I2 are already in the series as I^- and Br^-. The only one left for you to do is Cl^-. Since Cl2 is stronger than Br2 and I2, wouldn't Cl^- be the weakest of the three. Check my thinking.

  • chemistry - ,

    One other quick note. Make sure you want to list these with the strongest reducing agent at the top and the weakest at the bottom; otherwise, you need to reverse the order.

  • chemistry - ,

    One other quick note. Make sure you want to list these with the strongest reducing agent at the top and the weakest at the bottom; otherwise, you need to reverse the order.

    So Cl2
    Br2
    I2

    becomes

    I2
    Br2
    Cl2

    ?

  • chemistry - ,

    With them listed as
    Zn
    Pb
    Cu etc, we are looking at the half reactions as
    Zn ==> Zn^+2 + 2e
    Pb ==> Pb^+2 + 2e
    Cu ==> Cu^+2 + 2e
    These are written as oxidations and Zn is the strongest reducing agent with Pb and Cu following in order. Written as reductions (oxidizing agents) these would be Cu^+2 + 2e ==> Cu
    Pb^+2 + 2e ==> Pb.
    I don't remember the instructions from the original problem so I don't know how you want them arranged. The way the tables are arranged with the reactions, I THINK (but you must be the judge of that) that Zn, Pb, Cu, Ag, etc are the way it is to be done.

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