Posted by **Abigail** on Tuesday, April 15, 2008 at 5:05pm.

Please judge my answer

Question:A solution of AgNO3 (45 mL/0.45 M) was mixed with solution of NaCl (85 mL/1.35 x 10-2 M)

a) Calculate the ion product of the potential precipitate.

b) Would a precipitate form? The Ksp of AgCl(s) is 1.8 x 10-10.

Answer:

For a, doing the ion product is nessecary to get the answer. For part b of this question, comparing the ion product with Ksp is nessecary. Determining the ion product consists of using the formula Kw=Ka/Kb, for Ka I would do 0.0045/0.0085 = 0.529 and for Kb, I would do 0.45/0.0135 = 33.33. I would then use the formula Kw = Ka/Kb to get a value of 1.0 x 10^-2. This is my ion product value. When comparing the ion product to Ksp, I see that 1.0 x 10^-2 is greater than 1.8 x 10^-10, therefore a precipitate will form.

## Answer This Question

## Related Questions

- chemistry - An AgNO3 solution (44 mL/0.44 M) has been mixed with an NaCl ...
- chemistry - Question:A solution of AgNO3 (45 mL/0.45 M) was mixed with solution ...
- chemistry - Question:A solution of AgNO3 (45 mL/0.45 M) was mixed with solution ...
- Chemistry - If 845mL of a 2.5x10^-5 mol/L solution of Ni(NO3)2 was mixed with ...
- AP CHEMISTRY - SOMEONE PLEASE EXPLAIN AND ANSWER THIS QUESTION : Will Co(OH)2 ...
- Chemistry - Silver chloride has Ksp=1.6x10^-10 and silver cheomate has Ksp=9....
- chemistry - 24.8 mL sample of a 4.63 x 10–2 M solution of NaCl is mixed with a ...
- ap chemistry - When 50.0 mL of a 0.010 M CuNO3 solution is mixed with 150.0 mL ...
- Chemistry - Consider the following reaction AgNO3 (aq) + NaCl (aq) → AgCl...
- Chemistry (Ksp and Solubility) - Kindly answer my query as early as possible....

More Related Questions