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April 19, 2014

Homework Help: chemistry

Posted by Abigail on Tuesday, April 15, 2008 at 5:05pm.

Please judge my answer


Question:A solution of AgNO3 (45 mL/0.45 M) was mixed with solution of NaCl (85 mL/1.35 x 10-2 M)
a) Calculate the ion product of the potential precipitate.
b) Would a precipitate form? The Ksp of AgCl(s) is 1.8 x 10-10.



Answer:
For a, doing the ion product is nessecary to get the answer. For part b of this question, comparing the ion product with Ksp is nessecary. Determining the ion product consists of using the formula Kw=Ka/Kb, for Ka I would do 0.0045/0.0085 = 0.529 and for Kb, I would do 0.45/0.0135 = 33.33. I would then use the formula Kw = Ka/Kb to get a value of 1.0 x 10^-2. This is my ion product value. When comparing the ion product to Ksp, I see that 1.0 x 10^-2 is greater than 1.8 x 10^-10, therefore a precipitate will form.

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