Posted by **Abigail** on Tuesday, April 15, 2008 at 4:56pm.

Please let me know if my answer to the following question is correct.

Question:

What is the concentration of a weak base if its Kb = 1.4 x 10-11 and its pH = 8.75?

Answer:

Converting pH to H^+ concentration using the formula H^+ = 10^-ph, therefore 10^-8.75 gives an H^+ concentration value of 1.0 x 10^-9. Now, using the formula Ka=Kw/Kb and subsitituing in the values (Ka = 1.4 x10^-14/1.4 x 10^-11) gives 1.0 x 10^-3.

Now, subtracting 1.0 x 10^-3 from 1.0x 10^-9 gives a concentration of 9.9 x 10^-4 mol/L

- chemistry -
**DrBob222**, Tuesday, April 15, 2008 at 5:34pm
No, I don't think so. First, pH = 8.75 gives (H^+) = 1.77 x 10^-9.

Then I would say (OH^-) = Kw/(H^+) = ??

Then BOH <==>B^+ + OH^-

Kb = (B^+)(OH^-)/(BOH) = 1.4 x 10^-11

You now have (B^+)=(OH^-) = 5.62 x 10^-6 and you can solve for (BOH).

- chemistry -
**Abigail**, Tuesday, April 15, 2008 at 5:38pm
rats....:)

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