Friday
April 25, 2014

Homework Help: Chemistry

Posted by LT on Monday, April 14, 2008 at 8:06pm.

what is the molar solubility of lead sulfate in 1.0 X 10^-3 M Na2SO4?

The Solubility Product Constant PbSO4

Ksp= 1.8 x 10^-8

The Ksp expression is:
Na2SO4 = [2Na][SO4^-2]

[2Na]=2x
[SO4^-2]=x

Ksp= 1.8 x 10^-8 = (x)(2x)
Ksp= 1.8 x 10^-8 /4x^3

1.8 x 10^-8/4 = x^3
4.5 x 10^-9 = x^3

is this right so far... what do i do next please

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