A woman finds the front windshield of her car covered with ice at -12.6°C. The ice has a thickness of 4.80 10-4 m, and the windshield has an area of 1.25 m2. The density of ice is 917 kg/m3. How much heat is required to melt the ice?

Use the area, thickness, and density to calculate the mass of ice.

Then mass ice x specific heat ice x 12.6 = joules necessary to raise the temperature of the ice to zero degrees C. then add in the amount to melt the ice which is mass ice x heat of fusion. Watch the units. Post your work if you get stuck.

Why did the ice go to therapy? Because it was feeling a little melt-ted!

Now, let's calculate the amount of heat required to melt the ice using the formula:

Q = m * L

Where:
Q is the heat required
m is the mass of the ice
L is the latent heat of fusion of ice

First, let's calculate the mass of the ice:

Volume of ice = thickness * area
Volume of ice = (4.80 * 10^-4 m) * (1.25 m^2)
Volume of ice = 6 * 10^-4 m^3

Mass of ice = density * volume
Mass of ice = 917 kg/m^3 * 6 * 10^-4 m^3
Mass of ice = 5.502 kg

Now, let's calculate the heat required:

Q = 5.502 kg * (3.33 * 10^5 J/kg)

So, the amount of heat required to melt the ice is approximately Q = 183.1616 * 10^5 J. Keep in mind that this is just an approximation, but who needs precision when you have a good laugh, right?

To find the amount of heat required to melt the ice, we can use the formula:

Q = m * L

Where:
Q is the heat required
m is the mass of the ice
L is the latent heat of fusion of ice.

First, let's find the mass of the ice.
We can calculate the volume of the ice using the formula:

V = A * d

Where:
V is the volume of the ice
A is the area of the windshield
d is the thickness of the ice.

V = 1.25 m^2 * 4.80 x 10^-4 m
= 6 x 10^-4 m^3

Next, we can calculate the mass of the ice using the formula:

m = V * ρ

Where:
m is the mass of the ice
V is the volume of the ice
ρ is the density of ice.

m = 6 x 10^-4 m^3 * 917 kg/m^3
= 5.502 kg

Now, let's calculate the heat required using the formula:

Q = m * L

Where:
Q is the heat required
m is the mass of the ice
L is the latent heat of fusion of ice.

The latent heat of fusion of ice is typically given as L = 334,000 J/kg.

Q = 5.502 kg * 334,000 J/kg
≈ 1,835,668 J

Therefore, approximately 1,835,668 Joules of heat are required to melt the ice.

To calculate the heat required to melt the ice, we need to use the equation:

Q = m * L

where Q is the heat required, m is the mass of the ice, and L is the latent heat of fusion for ice.

To find the mass of the ice, we can use the formula:

m = ρ * V

where m is the mass, ρ is the density of ice, and V is the volume of the ice.

First, let's calculate the volume of the ice. The volume (V) can be determined using the formula:

V = A * h

where A is the area of the windshield and h is the thickness of the ice.

Now, let's calculate the volume of the ice:

V = 1.25 m^2 * 4.80 * 10^-4 m = 6 * 10^-4 m^3

Next, let's calculate the mass of the ice:

m = 917 kg/m^3 * 6 * 10^-4 m^3 = 5.502 kg

Finally, we need to find the latent heat of fusion for ice, which is the amount of heat required to change 1 kg of ice into water at 0°C. The latent heat of fusion for ice is 334,000 J/kg.

Now, let's calculate the heat required to melt the ice:

Q = m * L = 5.502 kg * 334,000 J/kg = 1,834,668 J

Therefore, the heat required to melt the ice is approximately 1,834,668 Joules.