Posted by HELP Plz on Monday, April 14, 2008 at 2:35am.
It's done with moles.
You have acid acid for the acid so I don't know which acid you are using.
mols base = M x L = 0.1 x 0.002 L = xx
mols acid = M x L = 0.1 x 0.008 L = yy
There will be xx mols salt formd.
There will be xx mols acid - yy mols base = excess acid unreacted. All of the base will be gone.
The pH will be that of the acid/salt system but we need to know the acid to proceed.
I believe he was referring to hydrochloric acid
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