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November 24, 2014

November 24, 2014

Posted by **Lucy** on Sunday, April 13, 2008 at 9:53pm.

I need some help proving these identities:

*Oh, and I'm only in grade 11, so the identities we use are quotient identity and Pythagorean identity.

sinx/(sinx + cosx) = tanx/(1 + tanx)

cos^2x - sin^2x = 2cos^2x - 1

Thanks!

Lucy

- Math (trigonometry) -
**drwls**, Sunday, April 13, 2008 at 10:09pmBy inverting the fractions (a perfectly legal operation), the first equation can be converted to

(sin x + cos x)/sin x = (1 + tan x)/x

1 + cot x = 1 + 1/tan x

= 1 + cot x

In the second problem, substitute 1 - cos^2 x for sin^2 x on the left side.

- Math (trigonometry) -
**Lucy**, Sunday, April 13, 2008 at 10:26pmThanks for your help!

I understand the second problem now.

Except I'm confused about what you did in the first problem. We haven't learned anything about cotx yet...

I inverted the fractions, though and ended up with:

(sin x + cos x) / sin x = (1 + tan x) / tanx

(I'm just wondering...why did you write (1 + tan x) / x on the left side?)

Then simplifies to... cos x = 1 ??

I'm confused... :S

- Math (trigonometry) -
**Lucy**, Sunday, April 13, 2008 at 10:27pm*Sorry, should be:

I'm just wondering...why did you write (1 + tan x) / x on the *right* side?

Instead of (1 + tan x) / tan x?

- Math (trigonometry) -

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