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February 1, 2015

February 1, 2015

Posted by **matt** on Sunday, April 13, 2008 at 8:45pm.

four numbers. Find the number of possible passwords if there are no

restrictions on what three letters and what four numbers can be used.

- maths permutation and combination - answer pls check -
**matt**, Sunday, April 13, 2008 at 9:06pmPls check if my answer is correct

26C3*10C4

=26!/(26-3)!3! . 10!/(10-4)!4!

= 26*25*24*23!/23!*6 . 10*9*8*7*6!/6!*4*3*2*1

=15600/6 * 5040/24

=2600*210

=546000

- maths permutation and combination -
**bobpursley**, Sunday, April 13, 2008 at 9:38pmI didn't see that letters or numbers cant be used more than once.

26*26*26*26*10*10*10*10

As I read it AAAA0000 is allowed, your number didn't include those.

- maths permutation and combination -
**matt**, Sunday, April 13, 2008 at 9:44pmThanks

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