Posted by Jean on Sunday, April 13, 2008 at 1:26pm.
Use z-scores.
z = (x - mean)/sd
With your data:
z = (78 - 68.2)/10.4 = 0.94
.1736 is the probability using a z-table for a single student with a score greater than 78.
Now we can use a normal approximation to the binomial distribution.
mean = np = (75)(.1736) = 13
standard deviation = √np(1-p) = √(75)(.1736)(.8264) = 3.28
Again, use z-scores.
z = (20 - 13)/3.28 = 2.13
Use the z-table to find the probability. (Remember the problem says "at least 20" which means 20 or more.)
I hope this will help.
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