Posted by **Jean** on Sunday, April 13, 2008 at 1:26pm.

Scores on a test are normally distributed with a mean of 68.2 and a standard deviation of 10.4. Estimate the probability that among 75 randomly selscted students, at least 20 of them score greater that 78.

- statistics -
**MathGuru**, Tuesday, April 15, 2008 at 11:26pm
Use z-scores.

z = (x - mean)/sd

With your data:

z = (78 - 68.2)/10.4 = 0.94

.1736 is the probability using a z-table for a single student with a score greater than 78.

Now we can use a normal approximation to the binomial distribution.

mean = np = (75)(.1736) = 13

standard deviation = √np(1-p) = √(75)(.1736)(.8264) = 3.28

Again, use z-scores.

z = (20 - 13)/3.28 = 2.13

Use the z-table to find the probability. (Remember the problem says "at least 20" which means 20 or more.)

I hope this will help.

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