posted by mimi .
Find the standard form of the equation of the line that is perpendicular to -6x+5y=-6 and contains (8, -6)
By the way, thanks so much to anyone that can help me! (I forgot to add that before!)
The slope of the line
can be seen by rewriting it as
y = (6/5)x - 6/5
That slope is 6/5. A perpendicular line will therefore have slope -5/6.
Such a line passing through (8, -6) would have the equation
y +6 = (-5/6) (x-8)
y = -6 -(5/6)x + 40/6
y = (-5/6)x + (2/3)