Homework Help: Short Circuit Problem (Physics)

Posted by Eileen on Saturday, April 12, 2008 at 9:13pm.

Thanks so much for all your help damon!

I think this is my last one:

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The reading of the ammeter is 2 A. The reading of the voltmeter is 33 V. Determine the unknown resistance and emf (picture linked above- remove spaces).

Short Circuit Problem (Physics) - Dan, Saturday, April 12, 2008 at 9:39pm
emf sets top most node to emf V.

Nodal at top node:

(emf - V)/5 = 2A

=> emf = 43V

ohms law at top node:

(43V - 33V)/12 = Current right branch = 0.83A

Current in left branch = A + 0.83 = 2.83A

R = 33/2.83 = 11.66 Ohms

Although, this question is a little odd because there's no ground.
Short Circuit Problem (Physics) - Eileen, Saturday, April 12, 2008 at 9:43pm
ty so much dan!
Short Circuit Problem (Physics) - Dan, Saturday, April 12, 2008 at 9:52pm
No problem ^^

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