Posted by unknown on Saturday, April 12, 2008 at 7:46pm.
are you in my Peel online class too?
yes..im doing the acetic acid lab..still
The problem states that the mid-point of the titration is 12 mL (I assume that is 12 mL NaOH) so the equivalence point is 2 x 12 = 24 mL (double the mid-point).
Now you know
0.025 L acid x M acid = 0.024 L base x M base. But you need the M or ONE of them to calculate the other. Or at least you need some other information. I'm unfamiliar with the lab you are doing. Go back through it and see if there is any other information given. If so, I suggest you make a new post of it.
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