Tuesday

January 27, 2015

January 27, 2015

Posted by **Eileen** on Saturday, April 12, 2008 at 5:29pm.

Given the circuit above:

a) Solve for unknown currents.

b) What is the potential difference between points a and b?

c) If both batteries start with 20 A*h of charge, how long does it take the first of the batteries to run out? Which battery is it (left or right)?

d) If both 12V batteries are replaced by batteries of identical voltage, what is the smallest voltage which will result in integer currents throughout the circuit?

- Circuits Problem (Physics) -
**Damon**, Saturday, April 12, 2008 at 6:11pmSorry, can not open your image :(

- Circuits Problem (Physics) -
**Eileen**, Saturday, April 12, 2008 at 6:17pmhi,

i put spaces between the "h t t p :" because it wouldnt let me post it otherwise. if you delete the spaces it should load (i hope!).

- Circuits Problem (Physics) -
- Circuits Problem (Physics) -
**Damon**, Saturday, April 12, 2008 at 7:33pmI call the current coming out the top of the left battery i1

I call the current coming out the top of the right battery i2

Then the current headed down from a to b is (i1+i2) (Kirkhoff)

In the left loop

12 = 4 i1 + 6(i1+i2)

In the right loop

12 = 3 i2 + 6(i1+i2)

so

12 = 10 i1 + 6 i2

12 = 6 i1 + 9 i2

solve those two. I will multiply the first by three and the second by 2

36 = 30 i1 + 18 i2

24 = 12 i1 + 18 i2

subtract

12 = 18 i1

i1 = 2/3

then i2

12 = 10(2/3) + 6 i2

12 = 20/3 + 6 i2

36 = 20 + 18 i2

16 = 18 i2

i2 = 8/9

- Circuits Problem (Physics) -
**Damon**, Saturday, April 12, 2008 at 7:35pmb)

i1+i2 = 2/3 + 8/9 = 14/9

times the resistance which is 6 = 28/3 volts a above b

- Circuits Problem (Physics) -
**Damon**, Saturday, April 12, 2008 at 7:39pm2/3 = 6/9 = i1

8/9 = i2

so i2>i1 so the one on the right will run out first

(8/9) t = 20 amp hr

t = 9*20/8 = 9*5/2 = 22.5 hr

- Circuits Problem (Physics) -
**Damon**, Saturday, April 12, 2008 at 7:44pmat present i1 = 6/9 and i2 = 8/9

clearly if I multiply the voltages by 9 I will get 6 amps and 8 amps

then if I divide both voltages by two I will get 3 amps and 4 amps

so multiply the voltage by 9/2

(9/2)12 = 54 volts

- Circuits Problem (Physics) -
**Eileen**, Saturday, April 12, 2008 at 9:31pmomg! thankss!!

**Answer this Question**

**Related Questions**

Short Circuit Problem (Physics) - Thanks so much for all your help damon! I ...

Circuit Problem- Physics - I am trying to do these 2 problems. I'm starting out ...

[Physics] super hard/long circuit problem - I have this last one which is really...

Continued physics problem from before (way down) - Posted by Eileen on Sunday, ...

Physics - 1)A 2.0-V battery is connected in a circuit with an ammeter and an ...

Funky Lens Problem - img14.imageshack.us/my.php?image=funkylensproblem.tif

physics - Given circuits for f and f−1, we can create classical reversible...

Physics - IMAGE: img7.imageshack.us/img7/4994/lenses.png Do I use the image ...

College physics - Find the following potential differences. The magnitude of the...

Science - To find the current in a complex circuit, it is necessary to know the ...