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March 31, 2015

March 31, 2015

Posted by **Kyle** on Friday, April 11, 2008 at 8:49pm.

Thanks in advance.

- Physics / Dynamics -
**drwls**, Saturday, April 12, 2008 at 12:29amdw/dt = -b - c w^2

Solve by separation of variables

dt = -dw/(b + c w^2)

= -(dw/c)/[(b/c) + w^2]

Integrate the left side from t=0 to T while the right side goes from w_o to 0

The term on the right integrates to an arctangent function.

T = (1/c)*sqrt(c/b)[tan^-1(sqrt(c/b)w_o)) - tan^-1(0]

sqrt(1/bc)*tan^-1{sqrt[(c/b)*w_o]}

No guarantees on that. Try it yourself

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