algebra1
posted by deshaun on .
Colin invested $32,000, part at 8% and part at 12%. If the total interest at the end of the year is $3,160, how much did he invest at each rate?

X = amount invested at 0.08.
32000X = amount invested at 0.12.
X(0.08) + (32000x)(0.12) = 3160
Solve for x and 32000x.
Check my thinking. Check my work.