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December 21, 2014

December 21, 2014

Posted by **Jon** on Friday, April 11, 2008 at 4:08pm.

an accelerating charged particle or changing magnetic fields.

2)Find the period of an electromagnetic wave of wavelength 2.20 x 10^-2 m.

3.00 x 10^8 * 2.20 x 10^-2

= 6.60 x 10^6 s

- Physics -
**bobpursley**, Friday, April 11, 2008 at 6:26pm2) 1/period*wavelength=speedoflight

period=wavelength/speedoflight.

Also, think about your answer. A million seconds for one period? Goodness.

- Physics -
**Jon**, Friday, April 11, 2008 at 7:15pm2)I don't really understand 1/period*wavelength. I can't multiply period times wavelength if I dont know the period. but I did get a different answer. my book doesnt show me how to find the period I just used wavelength-frequency relationship for a wave equation to find the frequency

2.20 x 10^-2/3.00 x 10^8

= 7.33 x 10^-11

these are my choices by the way:

A)1.36 x 10^10

B)4.54 x 10^1

C)7.33 x 10^-11

D)6.60 x 10^6

- Physics -
**drwls**, Friday, April 11, 2008 at 10:05pmfrequency = (speed of light)/(wavelength)

= 3*10^8 m/s/(2.2*10^-2 m)

Looks like (A) to me.

All I did was rearrange the equation BobPursley gave you.

If you would label your calculations with dimensions, and write down your equations, it would be easier for you to find your own errors. Once again, it seems you are just plugging in numbers at random.

- Physics -
**Jon**, Friday, April 11, 2008 at 10:21pmthank you but no I did not 3.00 x 10^8 is the speed of light constant I got from my book not out of my head thats what I use to find the wavelength

- Physics -
**Jon**, Friday, April 11, 2008 at 10:38pmthe answer was C

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