1)A 0.050 m long wire is carrying a current of 2.0 A at right angles to a 0.15 T magnetic field. What is the magnitude of the force exerted by the magnetic field on the wire?
F=ILB
(0.050)(2.0)(0.15)
0.015 N
2)Which device is used to measure very small currents?
galvanometer
Both answers are correct :-)
To find the magnitude of the force exerted by the magnetic field on the wire, you can use the formula:
F = I * L * B
where F is the force, I is the current, L is the length of the wire, and B is the magnetic field strength.
In this case, the length of the wire is given as 0.050 m, the current is 2.0 A, and the magnetic field strength is 0.15 T. Plugging in these values into the formula, we get:
F = (0.050) * (2.0) * (0.15)
= 0.015 N
Therefore, the magnitude of the force exerted by the magnetic field on the wire is 0.015 N.
For the second question, the device used to measure very small currents is a galvanometer. A galvanometer is an instrument that detects and measures electric current, particularly weak currents. It works by using the magnetic field produced by the electric current to deflect a needle or a coil, which can then be read on a scale to determine the current strength. Galvanometers are commonly used in scientific research, electrical engineering, and in many electronic devices.