Posted by LT on Thursday, April 10, 2008 at 10:11pm.
Ca(OH)2 ==> Ca^+2 + 2OH^-
pH = 12.35
pOH = 14-12.35
Calculate (OH^-).
Convert (OH^-) to (Ca^+2)
Calculate Ksp = (Ca^+2)(OH^-)^2
Post your work if you get stuck.
I follow you so far but how do you calculate OH
pOH = 1.65 = -log(OH^-).
Do you know how to solve that?
-log(OH^-) = 1.65
log(OH^-) = -1.65
Enter -1.65 in your calculator and hit the 10x key. Tht will give you 0.022387 31M. (That is more places than you can use but that's the number that shows up on my calculator.)
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