verify the identities:
1.) 2tanx-(1+tanx)^2 = -secx
*the ãis only over the 3*
any help is greatly appreciated!!
Math (Trig) typo edit - Hailey, Thursday, April 10, 2008 at 8:49am
ã is supposed to represent square root.
so for number 2
it's 1/2 (square root 3 cosx-sinx)
Math (Trig) a.s.a.p, thanks! - Reiny, Thursday, April 10, 2008 at 11:57am
LS = 2sinx/cosx - (1+sinx/cosx)^2
= 2sinx/cosx - ((cosx + sinx)/cosx)
= 2sinx/cosx - (cos^2 x + 2sinxcosx + sin^2 x)/cos^2 x
= (2sinxcosx -(1 + 2sinxcosx))/cos^2 x
= -1/cos^2 x
= -sec^2 x
you had -secx on the right side
I think you made a typo
2. LS = cosxcos330 + sinxsin330
but sin 330 = -sin30 = -1/2
and cos 330 = cos30 = √3/2
= (√3/2)cosx - 1/2 sinx
= 1/2(√3 cosx - sinx)
Why don't you try the third one.
Change everything to sines and cosines
let me know how you did.
Math (Trig) a.s.a.p, thanks! - Reiny, Thursday, April 10, 2008 at 12:07pm
for the third one you had
Your lack of brackets made this ambiguous.
I tried (1+cos2x)/sinx=cotx and tested with 40º, did not work
I tried 1+cos^2 x/sinx=cotx and tested with 40º, did not work
I tried 1+(cos2x/sinx)=cotx and tested with 40º, did not work
check your typing of the question.