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April 19, 2014

Homework Help: Chemistry

Posted by Lloyd on Thursday, April 10, 2008 at 3:30am.

What is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x 10^-10?

I am not sure how to this question... I did 6.2x10^-10/ 1.24?? I am not sure if it is right OR are we suppose to find the Kb value which i already did Kb= kw/ka = 1.0x10^-14/6.2x10^-10 = 1.61x10^-5 then divide it by 1.24 = 1.30X10^-5???

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