Posted by Laura on Wednesday, April 9, 2008 at 10:21pm.
Let's call a weak base BOH.
BOH ==> B^+ + OH^-
Kb = (B^+)(OH^-)/(BOH)
Look at the ICE chart.
I = initial concn (before ionization):
BOH = 1.4 mols/L.
(B^+) = 0
(OH^-) = 0
C = change in concn:
(B+) = +1.4*0.0063
(OH^-) = +1.4*0.0063
(BOH^-) = 1.4*0.9937 (0.9937 is the fraction from 100%-0.63% = 99.37%)
E = equilibrium concn:
(B^+) = 1.4*0.0063 = ??
(OH^-) = 1.4^0.0063 = ??
(BOH) = 1.4-(1.4*0.0063) OR (1.4*0.9937= ??)
Substitute the equilibrium numbers into Ka expression and calculate Ka.
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