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Posted by on Wednesday, April 9, 2008 at 9:27pm.

What is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x 10-10

  • chemistry - , Wednesday, April 9, 2008 at 10:52pm

    Show me what you know about this and I can help you through it.

  • chemistry - , Thursday, April 10, 2008 at 3:09am

    i know nothign abt it but can u help me through it.

  • chemistry - , Thursday, April 10, 2008 at 10:46am

    I'm sure you know something.
    Write the equation.
    HCN ==> H^+ + CN^-
    Write the Ka expression.
    Ka = (H^+)(CN^-)/(HCN) = 6.32 x 10^-10

    Set up the ICE table and go from there.

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