posted by unknown on .
What is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x 10-10
Show me what you know about this and I can help you through it.
i know nothign abt it but can u help me through it.
I'm sure you know something.
Write the equation.
HCN ==> H^+ + CN^-
Write the Ka expression.
Ka = (H^+)(CN^-)/(HCN) = 6.32 x 10^-10
Set up the ICE table and go from there.